AP EAMCET · Maths · Hyperbola
The equation of the pair of asymptotes of the hyperbola \(x^2-2 y^2-8 x+8 y+4=0\) is
- A \(x^2-2 y^2-8 x+8 y-8=0\)
- B \(2 x^2-4 y^2-16 x+16 y-7=0\)
- C \(x^2-2 y^2-8 x+8 y+8=0\)
- D \(2 x^2-4 y^2-16 x+16 y+9=0\)
Answer & Solution
Correct Answer
(C) \(x^2-2 y^2-8 x+8 y+8=0\)
Step-by-step Solution
Detailed explanation
\(\because x^2-2 y^2-8 x+8 y+4=0\) \(\begin{aligned} & \Rightarrow \quad(x-4)^2-2(y-2)^2-16 \\ & \Rightarrow \quad(x-4)^2-2(y-2)^2=4\end{aligned}\) Then, the equation of asymptote is…
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