AP EAMCET · Maths · Permutation Combination
All letters of the word 'AGAIN' are permuted in all possible ways and the words so formed (with or without meaning) are written as in a dictionary, then the \(50{ }^{\text {th }}\) word is
- A IAANG
- B INAGA
- C NAAIG
- D NAAGI
Answer & Solution
Correct Answer
(C) NAAIG
Step-by-step Solution
Detailed explanation
Words starting with A: \( \frac{4!}{2!} = 12 \) (Incorrect, one A is used, so 4!/1! from remaining A, G, I, N) Words starting with A: \( \frac{4!}{1!} = 24 \) (A, G, I, N. The remaining A is distinct from G, I, N) Words starting with G: \( \frac{4!}{2!} = 12 \) (A, A, I, N)…
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