AP EAMCET · Maths · Differentiation
\(\begin{aligned} & y=\sin \left(\log \left(x^2+2 x+1\right)\right) \\ & \Rightarrow(x+1)^2 \frac{d^2 y}{d x^2}+(x+1) \frac{d y}{d x}=\end{aligned}\)
- A \(y\)
- B \(-4 y\)
- C \(4 y\)
- D \(-y\)
Answer & Solution
Correct Answer
(B) \(-4 y\)
Step-by-step Solution
Detailed explanation
(b) Given, \(y=\sin \left(\log \left(x^2+2 x+1\right)\right)\) \[ \Rightarrow \quad y=\sin [2 \log (x+1)] \] So, \(\frac{d y}{d x}=\left[\cos (2 \log (x+1)] \times\left(\frac{2}{x+1}\right)\right.\) \[ \Rightarrow \quad(x+1) \frac{d y}{d x}=2 \cos (2(\log (x+1)) \] On…
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