AP EAMCET · Maths · Properties of Triangles
The perimeter of \(\triangle A B C\) is \(36 \mathrm{~cm}\) and its in radius is \(8 \mathrm{~cm}\). Then, the area of the triangle is
- A \(144 \mathrm{~cm}^2\)
- B \(124 \mathrm{~cm}^2\)
- C \(164 \mathrm{~cm}^2\)
- D \(104 \mathrm{~cm}^2\)
Answer & Solution
Correct Answer
(A) \(144 \mathrm{~cm}^2\)
Step-by-step Solution
Detailed explanation
In radius \((r)=\frac{\Delta}{S}\) \(\begin{aligned} \Delta & =(r \cdot s), \Delta \rightarrow \text { Area, } S \rightarrow \text { Semi-perimeter } \\ \Rightarrow \quad \Delta & =8 \times \frac{36}{2}=144 \mathrm{~cm}^2 \end{aligned}\)
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