AP EAMCET · Maths · Probability
\(\mathrm{P}, \mathrm{Q}\) and R try to hit the same target one after the other. If their probabilities of hitting the target are \(\frac{2}{3}, \frac{3}{5}, \frac{5}{7}\) respectively, then the probability that the target is hit by P or Q but not by R is
- A \(\frac{26}{105}\)
- B \(\frac{79}{105}\)
- C \(0\)
- D \(\frac{75}{105}\)
Answer & Solution
Correct Answer
(A) \(\frac{26}{105}\)
Step-by-step Solution
Detailed explanation
Let \(P=\) The event that \(P\) hit target \(\mathrm{Q}=\) The event that Q hit target \(\mathrm{R}=\) The event that R hit target \(\because \mathrm{P}(\mathrm{P})=\frac{2}{3}, \mathrm{P}(\mathrm{Q})=\frac{3}{5}\) and \(\mathrm{P}(\mathrm{R})=\frac{5}{7}\) Now, required…
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