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AP EAMCET · Maths · Differentiation

\(\begin{aligned} & \text { If } y=\tan ^{-1}\left\{\frac{x}{1+\sqrt{1-x^2}}\right\} \\ & +\sin \left\{2 \tan ^{-1} \sqrt{\frac{1-x}{1+x}}\right\} \text {, then } \frac{d y}{d x}=\end{aligned}\)

  1. A \(\frac{1-2 x}{2 \sqrt{1-x^2}}\)
  2. B \(\frac{1-2 x}{x \sqrt{1-x^2}}\)
  3. C \(\frac{2 x+1}{x \sqrt{1-x}}\)
  4. D \(\frac{2-x}{2 \sqrt{1-x^2}}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{1-2 x}{2 \sqrt{1-x^2}}\)

Step-by-step Solution

Detailed explanation

Given that, \[ y=\tan ^{-1}\left\{\frac{x}{1+\sqrt{1-x^2}}\right\}+\sin \left\{2 \tan ^{-1} \sqrt{\frac{1-x}{1+x}}\right\} \] Let \(x=\cos 2 \theta\)…