AP EAMCET · Maths · Differentiation
\(\begin{aligned} & \text { If } y=\tan ^{-1}\left\{\frac{x}{1+\sqrt{1-x^2}}\right\} \\ & +\sin \left\{2 \tan ^{-1} \sqrt{\frac{1-x}{1+x}}\right\} \text {, then } \frac{d y}{d x}=\end{aligned}\)
- A \(\frac{1-2 x}{2 \sqrt{1-x^2}}\)
- B \(\frac{1-2 x}{x \sqrt{1-x^2}}\)
- C \(\frac{2 x+1}{x \sqrt{1-x}}\)
- D \(\frac{2-x}{2 \sqrt{1-x^2}}\)
Answer & Solution
Correct Answer
(A) \(\frac{1-2 x}{2 \sqrt{1-x^2}}\)
Step-by-step Solution
Detailed explanation
Given that, \[ y=\tan ^{-1}\left\{\frac{x}{1+\sqrt{1-x^2}}\right\}+\sin \left\{2 \tan ^{-1} \sqrt{\frac{1-x}{1+x}}\right\} \] Let \(x=\cos 2 \theta\)…
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