AP EAMCET · Maths · Heights and Distances
A tower subtends angles \(\alpha, 2 \alpha\) and \(3 \alpha\) respectively at points \(A, B\) and \(C\), all lying on a horizontal line through the foot of the tower, then \(\frac{A B}{B C}\) is equal to:
- A \(\frac{\sin 3 \alpha}{\sin 2 \alpha}\)
- B \(1+2 \cos 2 \alpha\)
- C \(2 \cos 2 \alpha\)
- D \(\frac{\sin 2 \alpha}{\sin \alpha}\)
Answer & Solution
Correct Answer
(B) \(1+2 \cos 2 \alpha\)
Step-by-step Solution
Detailed explanation
In \(\triangle E C D\), \(\tan 3 \alpha=\frac{h}{C D}\) \(\Rightarrow \quad C D=h \cot 3 \alpha \quad \ldots(\mathrm{i})\) In \(\triangle E B D\), \(\tan 2 \alpha=\frac{h}{B D}\) \(\Rightarrow \quad B D=h \cot 2 \alpha \quad \ldots(\mathrm{ii})\) In \(\triangle E A D\),…
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