AP EAMCET · Maths · Probability
\(A\) speaks truth in \(20 \%\) of the cases and \(B\) in \(80 \%\) of the cases. Find the probability that their statements about an incident do not match.
- A \(\frac{3}{25}\)
- B \(\frac{17}{25}\)
- C \(\frac{4}{25}\)
- D \(\frac{8}{25}\)
Answer & Solution
Correct Answer
(B) \(\frac{17}{25}\)
Step-by-step Solution
Detailed explanation
Let \(E_1\) be the event of \(A\) speaking the truth \(\begin{aligned} \therefore \quad & P\left(E_1\right)=\frac{20}{100}=\frac{1}{5} \\ & P\left(\overline{E_1}\right)=1-\frac{1}{5}=\frac{4}{5} \end{aligned}\) \(E_2\) be the event of \(B\) speaking the truth.…
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