AP EAMCET · Maths · Three Dimensional Geometry
The angle between the lines whose direction cosines are given by the equations \(l^2+m^2-n^2=0\) and \(l+m+n=0\) is
- A \(\frac{\pi}{6}\)
- B \(\frac{\pi}{4}\)
- C \(\frac{\pi}{3}\)
- D \(\frac{\pi}{2}\)
Answer & Solution
Correct Answer
(C) \(\frac{\pi}{3}\)
Step-by-step Solution
Detailed explanation
Given, \[ \begin{aligned} l^2+m^2-n^2 & =0 ...(i)\\ l+m+n & =0 ...(ii) \end{aligned} \] By Eq. (ii), \(n=-(l+m)\) Put it Eq. (i), \(l^2+m^2=n^2\)…
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