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AP EAMCET · Maths · Probability

A problem is given to 3 students \(A, B\) and \(C\) whose chances of solving it are \(\frac{1}{2}, \frac{1}{3}\) and \(\frac{1}{4}\) respectively. Then, the probability of the problem being solved by exactly one of them, if all the three try independently, is

  1. A \(\frac{3}{4}\)
  2. B \(\frac{11}{24}\)
  3. C \(\frac{23}{24}\)
  4. D \(\frac{1}{4}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{11}{24}\)

Step-by-step Solution

Detailed explanation

The required probability…