AP EAMCET · Maths · Straight Lines
A point on the straight line \(3 x+5 y=15\) which is equidistant from the coordinate axes will lie in
- A either \(1^{\text {st }}\) quadrant or \(2^{\text {nd }}\) quadrant
- B \(4^{\text {th }}\) quadrant only
- C \(3^{\text {rd }}\) quadrant only
- D either in the \(3^{\text {rd }}\) or in the \(4^{\text {th }}\) quadrant
Answer & Solution
Correct Answer
(A) either \(1^{\text {st }}\) quadrant or \(2^{\text {nd }}\) quadrant
Step-by-step Solution
Detailed explanation
Let \(P\) be the point which is equidistant from the coordinate axis. \(\therefore \quad P\) lies on the line \(y=x\) or \(y=-x\). Let us find intersecting point of \(3 x+5 y=15\) and \(y=x\) for this, \(3 x+5 x=15 \Rightarrow 8 x=15 \Rightarrow x=\frac{15}{8}\) So,…
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