AP EAMCET · Maths · Parabola
A parabola having its axis parallel to \(\mathrm{Y}\)-axis, passes through the points \(\left(0, \frac{2}{5}\right),(4,-2)\) and \(\left(1, \frac{8}{5}\right)\); Then a point that lies on this parabola is
- A \((3,5 / 2)\)
- B \((-1,2)\)
- C \((-2,28 / 5)\)
- D \((2,8 / 5)\)
Answer & Solution
Correct Answer
(D) \((2,8 / 5)\)
Step-by-step Solution
Detailed explanation
Since, the axis of the parabola is parallel to y-axis. Then, \((x-h)^2=4 a(y-k)\) Since, \(e q^{\mathrm{n}}\) (i) passes through the given points \(\left(0, \frac{2}{5}\right)\), \((4,-2) \&\left(1, \frac{8}{5}\right)\)…
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