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AP EAMCET · Maths · Vector Algebra

The area of the parallelogram, whose diagonals are 2i^-j^+k^ and i^+3j^-k^, is equal to

  1. A 262 square units
  2. B 226 square units
  3. C 622 square units
  4. D 262 square units
Verified Solution

Answer & Solution

Correct Answer

(C) 622 square units

Step-by-step Solution

Detailed explanation

Area of parallelogram =12d→1×d→2 d→1×d→2=i^j^k^2-1113-1 =-2i^+3j^+7k^ d→1×d→2=62 Area =622 square units.