AP EAMCET · Maths · Application of Derivatives
The time \(T\) of oscillation of a simple pendulum of length \(L\) is governed by \(T=2 \pi \sqrt{\frac{L}{g}}\), where \(g\) is constant. The percentage by which the length be changed in order to correct an error of loss equal to 2 minutes of time per day is
- A \(-\frac{5}{18}\)
- B \(-\frac{2}{9}\)
- C \(\frac{1}{6}\)
- D \(\frac{1}{9}\)
Answer & Solution
Correct Answer
(A) \(-\frac{5}{18}\)
Step-by-step Solution
Detailed explanation
For simple pendulum of length \(L\), the time of oscillation is…
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