AP EAMCET · Maths · Straight Lines
A line \(L\) has intercepts \(a\) and \(b\) on the coordinate axes. When the axes are rotated through a given angle \(\theta\) keeping the origin fixed, this line \(L\) has the intercepts \(p\) and \(q\). Then
- A \(a^2+b^2=p^2+q^2\)
- B \(a^2+p^2=b^2+q^2\)
- C \(\frac{1}{a^2}+\frac{1}{p^2}=\frac{1}{b^2}+\frac{1}{q^2}\)
- D \(\frac{1}{a^2}+\frac{1}{b^2}=\frac{1}{p^2}+\frac{1}{q^2}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{a^2}+\frac{1}{b^2}=\frac{1}{p^2}+\frac{1}{q^2}\)
Step-by-step Solution
Detailed explanation
rotate the axis with respect to angle \(\alpha\) Put the values of Eq. (ii) in Eq. (i), we get…
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