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AP EAMCET · Maths · Limits

limz1z(1/3)1z(1/6)1=

  1. A -1
  2. B 1
  3. C 2
  4. D -2
Verified Solution

Answer & Solution

Correct Answer

(C) 2

Step-by-step Solution

Detailed explanation

limz→1 z(1/3)−1z(1/6)−1 We know that limx→a xm−amxn−an=mnam-n limz→1 z13−113z16−116 Here m = 13, n = 16 & a=1 =13161 =2.