AP EAMCET · Maths · Probability
A family consists of 8 persons. If 4 persons are chosen at random and they are found to be 2 men and 2 women, then the probability that there are equal number of men and women in that family is
- A \(\frac{1}{5}\)
- B \(\frac{3}{7}\)
- C \(\frac{2}{5}\)
- D \(\frac{2}{7}\)
Answer & Solution
Correct Answer
(D) \(\frac{2}{7}\)
Step-by-step Solution
Detailed explanation
Possible family compositions (men, women) where 2 men and 2 women can be chosen: \((2,6), (3,5), (4,4), (5,3), (6,2)\). Assuming uniform prior probabilities for these compositions, the posterior probability is proportional to the number of ways to choose 2 men and 2 women from…
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