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AP EAMCET · Maths · Vector Algebra

Let \(\mathbf{a}, \mathbf{b}\) and \(\mathbf{c}\) be three non-coplanar vectors. The vector equation of a line which passes through the point of intersection of two lines, one joining the points \(\mathbf{a}+2 \mathbf{b}-5 \mathbf{c}\), \(-\mathbf{a}-2 \mathbf{b}-3 \mathbf{c}\) and the other joining the points \(-4 \mathbf{c}, 6 \mathbf{a}-4 \mathbf{b}+4 \mathbf{c}\) is

  1. A \(r=2 a-4 b+3 c+\mu(a-6 b+4 c)\)
  2. B \(r=3 a+6 b-c+\mu(a+2 b+c)\)
  3. C \(\mathbf{r}=2 \mathrm{a}+3 \mathrm{~b}-\mathrm{c}+\mu(\mathrm{a}+\mathbf{b}-\mathbf{c})\)
  4. D \(r=-2 b+3 c+\mu(a-4 b+3 c)\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(r=3 a+6 b-c+\mu(a+2 b+c)\)

Step-by-step Solution

Detailed explanation

Equation of line joining the points, \(\mathbf{a}+2 \mathbf{b}-5 \mathbf{c},-\mathbf{a}-2 \mathbf{b}-3 \mathbf{c}\) is \[ \mathbf{r}=(\mathbf{a}+2 \mathbf{b}-5 \mathbf{c})+\lambda_1,(2 \mathbf{a}+4 \mathbf{b}-2 \mathbf{c}) \] Similarly, equation of the line joining the points…