AP EAMCET · Maths · Circle
The angle between the two tangents drawn from origin to the circle \(x^2+y^2-14 x+2 y+25=0\) is
- A \(0^{\circ}\)
- B \(45^{\circ}\)
- C \(90^{\circ}\)
- D \(60^{\circ}\)
Answer & Solution
Correct Answer
(C) \(90^{\circ}\)
Step-by-step Solution
Detailed explanation
Given equation of circle is \[ \begin{aligned} x^2+y^2-14 x+2 y+25 & =0 \\ \Rightarrow\left(x^2-14 x+49\right)+\left(y^2+2 y+1\right)-49-1+25 & =0 \\ (x-7)^2+(y+1)^2 & =25=5^2 \end{aligned} \] \(\Rightarrow \quad\) Radius of circle \(=5\) Centre of circle \(=(7,-1)\) Distance…
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