AP EAMCET · Chemistry · Hydrocarbons
Consider the following:
Statement-I : Kolbe's electrolysis of sodium propionate gives n-hexane as product
Statement-II : In Kolbe's process \(\mathrm{CO}_2\) is liberated at anode and \(\mathrm{H}_2\) is liberated at cathode
Correct answer is
- A Both statement-I and statement-II are correct
- B Both statement-I and statement-II are not correct
- C Statement-I is correct, but statement-II is not correct
- D Statement-I is not correct, but statement-II is correct
Answer & Solution
Correct Answer
(D) Statement-I is not correct, but statement-II is correct
Step-by-step Solution
Detailed explanation
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