AP EAMCET · Maths · Circle
A circle cuts off positive intercepts 5 and 6 on the \(x\) and \(y\) axes respectively, and passes through the origin. Then the equation of the circle is
- A \(x^2+y^2+5 x+6 y=0\)
- B \(x^2+y^2-5 x+6 y=0\)
- C \(x^2+y^2-5 x-6 y=0\)
- D \(x^2+y^2+5 x-6 y=0\)
Answer & Solution
Correct Answer
(C) \(x^2+y^2-5 x-6 y=0\)
Step-by-step Solution
Detailed explanation
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