AP EAMCET · Maths · Indefinite Integration
If \(\int \frac{5 \tan (x)}{\tan (x)-2} d x=x+a \log\)
\(|\sin (x)-2 \cos (x)|+k\), then \(a\) is equal to
- A -1
- B -2
- C 1
- D 2
Answer & Solution
Correct Answer
(D) 2
Step-by-step Solution
Detailed explanation
We have, \[ \int \frac{5 \tan x}{\tan x-2} d x=x+a \log |\sin x-2 \cos x|+K \] On differentiating, we get…
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