AP EAMCET · Maths · Probability
Two urns identical in appearance contain respectively 3 green and 2 black balls and 2 green and 5 black balls. One urn is selected at random and a ball is drawn from it. The probability that it is black is
- A \(\frac{39}{70}\)
- B \(\frac{37}{70}\)
- C \(\frac{41}{70}\)
- D \(\frac{33}{70}\)
Answer & Solution
Correct Answer
(A) \(\frac{39}{70}\)
Step-by-step Solution
Detailed explanation
There are two urns Urn 1 contains 3 green and 2 black balls. Urn 2 contains 2 green and 5 black balls. Let \(A\) be event of selecting black ball. Probability of selecting black ball from urn \(1=\frac{2}{5}\) Probability of selecting black ball from urn \(2=\frac{5}{7}\) Since,…
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