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AP EAMCET · Maths · Ellipse

The focal distances of the point 45,35 on the ellipse x24+y29=1 are

  1. A 103,23
  2. B 3,1
  3. C 133,53
  4. D 4,2
Verified Solution

Answer & Solution

Correct Answer

(D) 4,2

Step-by-step Solution

Detailed explanation

Given, Equation of ellipse x24+y29=1, So we can see b>a so it is vertical ellipse, Hence eccentricity is given by a2=b21-e2, ⇒4=91-e2 ⇒e=53 Now focus is given by 0,±be≡0,±5 Now assuming S≡0,5 & S'≡0,-5 and point P45,35,…