AP EAMCET · Maths · Probability
\(A\) and \(B\) are playing chess game with each other. The probability that \(A\) wins the game is 0.6, the probability that he loses is 0.3 and the probability its draw is 0.1. If they played three games, then the probability that \(A\) wins atleast two games is
- A \(\frac{54}{125}\)
- B \(\frac{81}{125}\)
- C \(\frac{18}{25}\)
- D \(\frac{9}{25}\)
Answer & Solution
Correct Answer
(B) \(\frac{81}{125}\)
Step-by-step Solution
Detailed explanation
\(P(\text{A wins}) = 0.6\) \(P(\text{A does not win}) = 1 - 0.6 = 0.4\) \(P(\text{A wins at least 2 games}) = P(\text{A wins 3 games}) + P(\text{A wins 2 games})\) \(P(\text{A wins 3 games}) = (0.6)^3 = 0.216\)…
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