AP EAMCET · Maths · Circle
The number of common tangents to the two circles \(x^2+y^2-8 x+2 y=0 \quad\) and \(x^2+y^2-2 x-16 y+25=0\) is :
- A 1
- B 2
- C 3
- D 4
Answer & Solution
Correct Answer
(B) 2
Step-by-step Solution
Detailed explanation
The equations of circles are \(x^2+y^2-8 x+2 y=0\) and \(x^2+y^2-2 x-16 y+25=0\) The centre and radius of first circle are \(C_1(4,-1)\) and \(\sqrt{17}\) respectively. Also the centre and radius of second circle are \(C_2(1,8)\) and \(\sqrt{40}\) respectively.…
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