AP EAMCET · Maths · Properties of Triangles
If in a \(\triangle A B C, r_1=2 r_2=3 r_3\), then the perimeter of the triangle is equal to
- A \(3a\)
- B \(3b\)
- C \(3c\)
- D \(3 (a+b+c)\)
Answer & Solution
Correct Answer
(B) \(3b\)
Step-by-step Solution
Detailed explanation
Given that, \(r_1=2 r_2=3 r_3\) Now, adding Eqs. (i), (ii) and (iii), we get \(\begin{aligned} & (s-a)+(s-b)+(s-c)=\Delta \mathrm{K}+2 \Delta \mathrm{K}+3 \Delta K \\ & 3 s-(a+b+c)=6 \Delta K \end{aligned}\) Since, we know \(a+b+c=2 s\)…
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