AP EAMCET · Maths · Parabola
The equation of the normal drawn to the parabola \(y^2=6 x\) at the point \((24,12)\) is
- A \(3 x-y=60\)
- B \(4 x+y=108\)
- C \(2 x+y=60\)
- D \(x-2 y=0\)
Answer & Solution
Correct Answer
(B) \(4 x+y=108\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { } y^2=6 x, \mathrm{P}(24,12) \\ & \Rightarrow 2 a=3 \end{aligned}\) Equation of normal in point form is \(\begin{aligned} & y-y_1=\frac{-y_1}{2 a}\left(x-x_1\right) \Rightarrow y-12=\frac{-12}{3}(x-24) \\ & \Rightarrow 4 x+y=108 \end{aligned}\)
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