AP EAMCET · Maths · Circle
The angle between the tangents drawn from the point \((2,2)\) to the circle \(x^2+y^2+4 x+4 y+c=0\) is \(\operatorname{Cos}^{-1}\left(\frac{7}{16}\right)\). If two such circles exist, then sum of the values of c is
- A 16
- B 20
- C -20
- D -16
Answer & Solution
Correct Answer
(D) -16
Step-by-step Solution
Detailed explanation
Center \(G(-2,-2)\), Point \(P(2,2)\). Distance \(d = \sqrt{(2 - (-2))^2 + (2 - (-2))^2} = \sqrt{32}\). Radius \(r = \sqrt{(-2)^2+(-2)^2-c} = \sqrt{8-c}\). Angle \(\theta\) between tangents: \(\cos\theta = 1 - 2\frac{r^2}{d^2}\). Case 1: \(\cos\theta = \frac{7}{16}\).…
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