AP EAMCET · Maths · Trigonometric Ratios & Identities
\(\frac{1-\cos (2 x)+\sin (x)}{\sin (2 x)+\cos (x)}=\)
- A \(\sin (x)\)
- B \(\cos (x)\)
- C \(\tan (x)\)
- D \(\operatorname{cosec}(x)\)
Answer & Solution
Correct Answer
(C) \(\tan (x)\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \frac{1-\cos 2 x+\sin x}{\sin 2 x+\cos x}=\frac{2 \sin ^2 x+\sin x}{2 \sin x \cos x+\cos x} \\ & \frac{\sin x(2 \sin x+1)}{\cos x(2 \sin x+1)}=\tan x. \end{aligned}\)
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