AP EAMCET · Maths · Vector Algebra
Let \(\vec{a}, \vec{b}, \vec{c}\) be co-initial vectors and \(\vec{a}=2 \hat{i}-\hat{j}+5 \hat{k}\) and \(\overrightarrow{\mathrm{b}}=3 \hat{\mathrm{i}}+7 \hat{\mathrm{j}}-\hat{\mathrm{k}}\). Let \((\overrightarrow{\mathrm{a}}, \overrightarrow{\mathrm{b}})=\theta\) be an acute angle and \(\overrightarrow{\mathrm{c}}\) be the vector along the bisector of the angle \(\theta\). If \(\lambda, x\), \(\mathrm{y} \in \mathbb{R}\), then \(\overrightarrow{\mathbf{c}}=\)
- A \(\lambda(5 \hat{\mathrm{i}}+6 \hat{\mathrm{j}}+4 \hat{\mathrm{k}})\)
- B \(\lambda(-\hat{\mathrm{i}}-8 \hat{\mathrm{j}}+6 \hat{\mathrm{k}})\)
- C \((2 x+3 y) \hat{i}+(7 y-x) \hat{j}+(5 x-y) \hat{k}\)
- D \((2 x+3 y) \hat{i}+(x+7 y) \hat{j}+(5 x+y) \hat{k}\)
Answer & Solution
Correct Answer
(C) \((2 x+3 y) \hat{i}+(7 y-x) \hat{j}+(5 x-y) \hat{k}\)
Step-by-step Solution
Detailed explanation
\(\because \overrightarrow{\mathrm{a}}=2 \hat{\mathrm{i}}-\hat{\mathrm{j}}+5 \hat{\mathrm{k}}, \overrightarrow{\mathrm{b}}=3 \hat{\mathrm{i}}+7 \hat{\mathrm{j}}-\hat{\mathrm{k}}\) Now, the angle bisector of vector \(\vec{a} \& \vec{b}\) are…
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