AP EAMCET · Maths · Circle
For the circle \(C\) with the equation \(x^2+y^2-16 x-12 y+64=0\) match the List I with the List II given below.
The correct match is
\(\begin{array}{llll}(\mathrm{i}) & (\mathrm{ii}) & (\mathrm{iii}) & (\mathrm{iv})\end{array}\)
- A \(\begin{array}{llll}(\mathrm{D}) & (\mathrm{B}) & (\mathrm{A}) & (\mathrm{E})\end{array}\)
- B \(\begin{array}{llll}(\mathrm{D}) & (\mathrm{A}) & (\mathrm{B}) & (\mathrm{E})\end{array}\)
- C \(\begin{array}{llll}(\mathrm{C}) & (\mathrm{D}) & (\mathrm{A}) & (\mathrm{B})\end{array}\)
- D \(\begin{array}{llll}(\mathrm{C}) & (\mathrm{E}) & (\mathrm{B}) & (\mathrm{A})\end{array}\)
Answer & Solution
Correct Answer
(B) \(\begin{array}{llll}(\mathrm{D}) & (\mathrm{A}) & (\mathrm{B}) & (\mathrm{E})\end{array}\)
Step-by-step Solution
Detailed explanation
Given equation of circle is \[ C=x^2+y^2-16 x-12 y+64=0 \] (i) Equation of polar at \((-5,1)\) w.r.t. to \(C\) is…
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