AP EAMCET · Chemistry · Chemical Kinetics
\(\mathrm{A} \rightarrow \mathrm{B}\) is a first order reaction. The concentration of A is decreased from \(x\) mol \(\mathrm{L}^{-1}\) to \(y \mathrm{~mol} \mathrm{~L}^{-1}\) in 100 min. What is the average velocity of the reaction in mol \(\mathrm{L}^{-1} \min ^{-1} ?\)
- A \(\frac{|x-y|}{100}\)
- B \(\frac{|y-x|^2}{100}\)
- C \(\frac{100}{|x-y|}\)
- D \(\frac{100}{|x+y|}\)
Answer & Solution
Correct Answer
(A) \(\frac{|x-y|}{100}\)
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