AP EAMCET · Chemistry · Electrochemistry
What is \(\mathrm{E}_{\text {cell }}\) (in V) of the following cell at 298 K ?
\(\left(\mathrm{E}_{\mathrm{Zn}^{2+} / \mathrm{Zn}}^{\ominus}=-0.76 \mathrm{~V} ; \mathrm{E}_{\mathrm{Ni}^{2+} / \mathrm{Ni}}^{\ominus}=-0.25 \mathrm{~V} ; \frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.06 \mathrm{~V}\right)\)
\(\mathrm{Zn}(\mathrm{s})\left|\mathrm{Zn}^{2+}(0.01 \mathrm{M}) \| \mathrm{Ni}^{2+}(0.1 \mathrm{M})\right| \mathrm{Ni}(\mathrm{s})\)
- A \(0.51\)
- B \(0.48\)
- C \(0.57\)
- D \(0.54\)
Answer & Solution
Correct Answer
(D) \(0.54\)
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