AP EAMCET · Chemistry · Surface Chemistry
The adsorption of a gas on a solid surface follows Freundlich adsorption isotherm.
At \(\mathrm{T}(\mathrm{K})\), the gas pressure is 2 atm. What is the value of \(\frac{x}{\mathrm{~m}} ? \quad(\mathrm{n}=2\) and \(k=\) constant)
- A \(\frac{x}{\mathrm{~m}}=4 \mathrm{k}\)
- B \(\frac{x}{\mathrm{~m}}=\frac{1.414}{\mathrm{k}}\)
- C \(\frac{x}{\mathrm{~m}}=\frac{\mathrm{k}}{1.414}\)
- D \(\frac{x}{\mathrm{~m}}=1.414 \mathrm{k}\)
Answer & Solution
Correct Answer
(D) \(\frac{x}{\mathrm{~m}}=1.414 \mathrm{k}\)
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