AP EAMCET · Chemistry · Chemical Bonding and Molecular Structure
\(\underline{X}\) and \(\underline{Y}\) are the two covalent molecules in which the hybridisation of the central atoms is same, but shapes are different. \(\underline{X}\) and \(\underline{Y}\) are
- A \(\mathrm{XeF}_4, \mathrm{NH}_3\)
- B \(\mathrm{XeF}_2, \mathrm{PF}_5\)
- C \(\mathrm{BF}_3, \mathrm{H}_2 \mathrm{O}\)
- D \(\mathrm{CH}_4, \mathrm{BeCl}_2\)
Answer & Solution
Correct Answer
(D) \(\mathrm{CH}_4, \mathrm{BeCl}_2\)
Step-by-step Solution
Detailed explanation
The hybridisation in \(\mathrm{XeF}_2\) and \(\mathrm{PF}_5\) both is \(s p^3 d\) thus they must have trigonal bi-pyramidal geometry. But, due to the presence of 3 lone pair and 2 bond pair shape of \(\mathrm{XeF}_2\) get distorted and the molecule appears linear. But in case of…
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