AP EAMCET · Chemistry · Thermodynamics (C)
The molar heats of fusion and vapourisation of benzene are 10.9 and \(31.0 \mathrm{~kJ} \mathrm{~mol}^{-1}\) respectively. The changes in entropy for the solid \(\rightarrow\) liquid and liquid \(\rightarrow\) vapour transitions for benzene are \(x\) and \(y . \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\), respectively. The value of \((y-x)\left(\right.\) in \(\left.\mathrm{JK}^{-1} \mathrm{~mol}^{-1}\right)\) is (At 1 atm, benzene melts at \(5.5^{\circ} \mathrm{C}\) and boils at \(80^{\circ} \mathrm{C}\) )
- A \(87.8\)
- B \(48.7\)
- C \(39.1\)
- D \(28.7\)
Answer & Solution
Correct Answer
(B) \(48.7\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \quad \Delta \mathrm{H}_{\text {fus }}\left(\mathrm{C}_6 \mathrm{H}_6\right)=10.9 \mathrm{~kJ} \mathrm{~mol}^{-1} \\ & \Delta \mathrm{H}_{\text {vap }}\left(\mathrm{C}_6 \mathrm{H}_6\right)=31.0 \mathrm{~kJ} \mathrm{~mol}^{-1} \\ & \text { Melting point of…
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