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AP EAMCET · Chemistry · Thermodynamics (C)

The molar heats of fusion and vapourisation of benzene are 10.9 and \(31.0 \mathrm{~kJ} \mathrm{~mol}^{-1}\) respectively. The changes in entropy for the solid \(\rightarrow\) liquid and liquid \(\rightarrow\) vapour transitions for benzene are \(x\) and \(y . \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\), respectively. The value of \((y-x)\left(\right.\) in \(\left.\mathrm{JK}^{-1} \mathrm{~mol}^{-1}\right)\) is (At 1 atm, benzene melts at \(5.5^{\circ} \mathrm{C}\) and boils at \(80^{\circ} \mathrm{C}\) )

  1. A \(87.8\)
  2. B \(48.7\)
  3. C \(39.1\)
  4. D \(28.7\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(48.7\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & \quad \Delta \mathrm{H}_{\text {fus }}\left(\mathrm{C}_6 \mathrm{H}_6\right)=10.9 \mathrm{~kJ} \mathrm{~mol}^{-1} \\ & \Delta \mathrm{H}_{\text {vap }}\left(\mathrm{C}_6 \mathrm{H}_6\right)=31.0 \mathrm{~kJ} \mathrm{~mol}^{-1} \\ & \text { Melting point of…