AP EAMCET · Maths · Probability
The following table shows the probability of selecting the boxes \(A, B\) and \(C\) and the number of balls of different colours contained in them.

- A \(\frac{1}{13}\)
- B \(\frac{6}{13}\)
- C \(\frac{5}{13}\)
- D \(\frac{7}{13}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{13}\)
Step-by-step Solution
Detailed explanation
Probability of green ball \(P(G)\) \[ \begin{aligned} & =\frac{1}{2} \times \frac{2}{6}+\frac{1}{3} \times \frac{3}{6}+\frac{1}{6} \times \frac{1}{6}=\frac{1}{6}+\frac{1}{6}+\frac{1}{36} \\ & =\frac{6+6+1}{36}=\frac{13}{36} \end{aligned} \] Let probability of drawn ball is green…
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