AP EAMCET · Chemistry · Solutions
At \(\mathrm{T}(\mathrm{K})\) two liquids A and B form an ideal solution. The vapour pressures of pure liquids A and B at that temperature are 400 and 600 mm Hg respectively. If the mole fraction of liquid \(B\) is 0.3 in the mixture, the mole fractions of \(A\) and \(B\) in vapour phase respectively are
- A 0.391,0.609
- B 0.509,0.491
- C 0.609,0.391
- D 0.491,0.509
Answer & Solution
Correct Answer
(C) 0.609,0.391
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { } \mathrm{P}_{\mathrm{A}}^0=400 \\ & \mathrm{P}_{\mathrm{B}}^0=600 \\ & \mathrm{x}_{\mathrm{A}}=0.7 \\ & \mathrm{x}_{\mathrm{B}}=0.3 \quad \left[\mathrm{x}_{\mathrm{A}}+\mathrm{x}_{\mathrm{B}}=1\right]\\\ &…
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