AP EAMCET · Chemistry · Structure of Atom
The radius of the first orbit of \(\mathrm{Li}^{2+}\) is \(\mathrm{X} Å\). The radius of the third orbit of \(\mathrm{He}^{+}\)(in \(Å\) ) is
- A \(\frac{18}{2} x\)
- B \(\frac{18}{3} x\)
- C \(\frac{27}{4} x\)
- D \(\frac{27}{2} x\)
Answer & Solution
Correct Answer
(D) \(\frac{27}{2} x\)
Step-by-step Solution
Detailed explanation
Radius of 1st Bohr orbit, \(\mathrm{r}=\frac{0.529 \mathrm{n}^2}{\mathrm{z}} Å\)…
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