AP EAMCET · Chemistry · Ionic Equilibrium
The molar solubility of \(\mathrm{PbI}_2\) in \(0.2 \mathrm{M} \mathrm{Pb}\left(\mathrm{NO}_3\right)_2\) solution in terms of \(\mathrm{K}_{\mathrm{sp}}\) (solubility product) is
- A \(\left(\frac{\mathrm{K}_{\mathrm{sp}}}{0.2}\right)^{1 / 2}\)
- B \(\left(\frac{\mathrm{K}_{\mathrm{sp}}}{0.4}\right)^{1 / 4}\)
- C \(\left(\frac{\mathrm{K}_{\mathrm{sp}}}{0.8}\right)^{1 / 2}\)
- D \(\left(\frac{\mathrm{K}_{\mathrm{sp}}}{0.8}\right)^{1 / 3}\)
Answer & Solution
Correct Answer
(C) \(\left(\frac{\mathrm{K}_{\mathrm{sp}}}{0.8}\right)^{1 / 2}\)
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