AP EAMCET · Chemistry · Coordination Compounds
Atomic number of \(\mathrm{Cr}, \mathrm{Fe}\) and \(\mathrm{Co}\) are 24, 26 and 27 respectively. Which of the following inner orbital octahedral complexes are paramagnetic?
- A \(\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}\)
- B \(\left[\mathrm{Co}(\mathrm{CN})_3\right]^{3+}\)
- C \(\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{4-}\)
- D \(\left[\mathrm{Cr}(\mathrm{CN})_6\right]^{3-}\)
Answer & Solution
Correct Answer
(D) \(\left[\mathrm{Cr}(\mathrm{CN})_6\right]^{3-}\)
Step-by-step Solution
Detailed explanation
\(\left[\mathrm{Cr}(\mathrm{CN})_6\right]^{3-}\) Oxidation state of \(\mathrm{Cr}: x+(-1) 6=-3\) \[ \begin{aligned} x & =+3 \\ \mathrm{Cr} & =[\mathrm{Ar}] 4 s^1 3 d^5 \\ \mathrm{Cr}^{3+} & =[\mathrm{Ar}] 4 s^0 3 d^3 \end{aligned} \] Since, \(\mathrm{CN}\) is a strong field…
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