AP EAMCET · Maths · Trigonometric Ratios & Identities
\(\sin ^4 \frac{\pi}{8}+\cos ^4 \frac{\pi}{8}+\sin ^4 \frac{3 \pi}{8}+\cos ^4 \frac{3 \pi}{8}+\sin ^4 \frac{5 \pi}{8}+\cos ^4 \frac{5 \pi}{8}+\sin ^4 \frac{7 \pi}{8}+\cos ^4 \frac{7 \pi}{8}=\)
- A 3
- B \(\frac{3}{2}\)
- C 4
- D 8
Answer & Solution
Correct Answer
(A) 3
Step-by-step Solution
Detailed explanation
\( \sin ^4 x + \cos ^4 x = 1 - 2\sin^2 x \cos^2 x = 1 - \frac{1}{2}\sin^2(2x) \)…
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