AP EAMCET · Chemistry · Thermodynamics (C)
The isotherms of an ideal gas at \(T_1, T_2, T_3\) along with their slopes (m) (in the brackets) are shown here. If \(T_1>T_2>T_3\), then the correct order of slopes of these isotherms is
- A \(m_2>m_1>m_3\)
- B \(m_3>m_2>m_1\)
- C \(\mathrm{m}_2>\mathrm{m}_3>\mathrm{m}_1\)
- D \(\mathrm{m}_1>\mathrm{m}_2>\mathrm{m}_3\)
Answer & Solution
Correct Answer
(D) \(\mathrm{m}_1>\mathrm{m}_2>\mathrm{m}_3\)
Step-by-step Solution
Detailed explanation
\(\mathrm{P}=\mathrm{nRT} \times \frac{1}{\mathrm{~V}}(\mathrm{y}=\mathrm{mx}+\mathrm{c}\) where \(\mathrm{c}=0)\) Thus, a higher value of \(\mathrm{T}\) would increase the value of the slope of the \(\mathrm{P}\) vs. \(\frac{1}{\mathrm{~V}}\) curve. Therefore, the correct order…
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