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AP EAMCET · Chemistry · Structure of Atom

The energy of an electron in an orbit of hydrogen like ion with an orbit radius of \(52.9 \mathrm{pm}\) in \(\mathrm{J}\) is (ground state energy of electron in hydrogen atom is \(=-2.18 \times 10^{-18} \mathrm{~J}\) )

  1. A \(-4.36 \times 10^{-18}\)
  2. B \(-1.09 \times 10^{-17}\)
  3. C \(-8.72 \times 10^{-18}\)
  4. D \(-6.54 \times 10^{-18}\)
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Correct Answer

(C) \(-8.72 \times 10^{-18}\)

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Given, Orbit radius \(=52.9 \mathrm{pm}\) Ground state energy of electron in hydrogen atom…
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