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AP EAMCET · Chemistry · Coordination Compounds

The correct order about the number of unpaired electrons present in the following complexes is
\[
\left.\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{4-} \underset{\text { II }}{\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}} \underset{\text { III }}{\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6}\right]^{2+}
\]

  1. A II \(>\) III \(>\) I
  2. B II \(>\) I \(>\) III
  3. C I \(>\) II \(>\) III
  4. D III \(>\) II \(>\) I
Verified Solution

Answer & Solution

Correct Answer

(A) II \(>\) III \(>\) I

Step-by-step Solution

Detailed explanation

I. \(\left[\mathrm{Fe}(\mathrm{CN})_6 \mathrm{I}^{4-}\right.\) Atomic number of \(\mathrm{Fe}=26\) Ground state configuration of \(\mathrm{Fe}=[\mathrm{Ar}] 3 d^6 4 s^2\) \[ \mathrm{Fe}^{2+}=[\mathrm{Ar}] 3 d^6 \] Since, cyanide is a powerful ligand, therefore, all the electrons…