AP EAMCET · Chemistry · Thermodynamics (C)
The atomisation enthalpy of \(\mathrm{CH}_4\) is \(1660 \mathrm{~kJ} \mathrm{~mol}^{-1}\). The \(\mathrm{C}-\mathrm{H}\) bond enthalpy of each successive step in
\(\mathrm{CH}_4 \rightarrow \mathrm{CH}_3 \rightarrow \mathrm{CH}_2 \rightarrow \mathrm{CH}\) are \(+15,+30\) and \(+45 \mathrm{~kJ} \mathrm{~mol}^{-1}\) higher than the mean bond enthalpy of \(\mathrm{CH}\) bonds, respectively. The bond enthalpy of the last \(\mathrm{C}-\mathrm{H}\) unit is
- A \(400 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
- B \(325 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
- C \(475 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
- D \(385 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
Answer & Solution
Correct Answer
(B) \(325 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
Step-by-step Solution
Detailed explanation
The atomisation enthalpy of \(\mathrm{CH}_4\) is \(1660 \mathrm{~kJ} \mathrm{~mol}^{-1}\). \(\mathrm{CH}_4(g) \longrightarrow \mathrm{C}(g)+4 \mathrm{H}(g) ; \quad \Delta_a H=1660 \mathrm{kJmol}^{-1}\)…
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