AP EAMCET · Chemistry · Solutions
A solution is prepared by dissolving \(10 \mathrm{~g}\) of a non-volatile solute (molar mass, ' \(M^{\prime} \mathrm{g} \mathrm{mol}^{-1}\) ) in \(360 \mathrm{~g}\) of water. What is the molar mass in \(\mathrm{g} \mathrm{mol}^{-1}\) of solute if the relative lowering of vapour pressure of solution is \(5 \times 10^{-3}\) ?
- A 199
- B 99.5
- C 299
- D 149.5
Answer & Solution
Correct Answer
(B) 99.5
Step-by-step Solution
Detailed explanation
Given, Mass of solute \(\left(w_B\right)=10 \mathrm{~g}\) Molar mass of solute \(\left(M_B\right)=M_B\) Mass of solvent \(\left(w_A\right)=360 \mathrm{~g}\) Relative lowering in vapour pressure of solution \[ =5 \times 10^{-3} \] Molar mass of water…
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