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AP EAMCET · Chemistry · Solid State

Calculate the coordination number of \(\mathrm{Na}^{+}\)in \(\mathrm{NaCl}\) crystal, given radius of \(\mathrm{Na}^{+}\)and \(\mathrm{Cl}^{-}\)are \(95 \mathrm{pm}\) and \(181 \mathrm{pm}\) respectively.

  1. A 8
  2. B 4
  3. C 6
  4. D 12
Verified Solution

Answer & Solution

Correct Answer

(C) 6

Step-by-step Solution

Detailed explanation

For \(\mathrm{NaCl}\) crystal Radius ratio, \(\frac{r_{\mathrm{Na}^{+}}}{r_{\mathrm{Cl}^{-}}}=\frac{95}{181}=0.5248\), which is, in the range of \(0.414-0.732\). So, coordination number of \(\mathrm{Na}^{+}\)in \(\mathrm{NaCl}\) crystal \(=6\)