AP EAMCET · Chemistry · p Block Elements (Group 15, 16, 17 & 18)
The product obtained at anode when \(50 \%\) \(\mathrm{H}_2 \mathrm{SO}_4\) aqueous solution is electrolysed using platinum electrodes is :
- A \(\mathrm{H}_2 \mathrm{SO}_3\)
- B \(\mathrm{H}_2 \mathrm{~S}_2 \mathrm{O}_8\)
- C \(\mathrm{O}_2\)
- D \(\mathrm{H}_2\)
Answer & Solution
Correct Answer
(B) \(\mathrm{H}_2 \mathrm{~S}_2 \mathrm{O}_8\)
Step-by-step Solution
Detailed explanation
\(50 \% \mathrm{H}_2 \mathrm{SO}_4\) aqueous solution can be electrolysed by using Pt electrodes as \(2 \mathrm{H}_2 \mathrm{SO}_4 2 \mathrm{HSO}_4^{-}+2 \mathrm{H}^{+}\) \(2 \mathrm{HSO}_4^{-} \longrightarrow \mathrm{H}_2 \mathrm{~S}_2 \mathrm{O}_8+2 e^{-}\)(at anode)
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